Base | Representation |
---|---|
bin | 1001000011010101110… |
… | …10010100110111000001 |
3 | 1002201211022022010221120 |
4 | 10201222322110313001 |
5 | 20043443004220001 |
6 | 354515200342453 |
7 | 31320434412213 |
oct | 4415272246701 |
9 | 1081738263846 |
10 | 311031320001 |
11 | 10a9a9087296 |
12 | 50343914a29 |
13 | 2343a3a0cac |
14 | 110a82465b3 |
15 | 8155d88236 |
hex | 486ae94dc1 |
311031320001 has 4 divisors (see below), whose sum is σ = 414708426672. Its totient is φ = 207354213332.
The previous prime is 311031319993. The next prime is 311031320009. The reversal of 311031320001 is 100023130113.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is an interprime number because it is at equal distance from previous prime (311031319993) and next prime (311031320009).
It is a cyclic number.
It is not a de Polignac number, because 311031320001 - 23 = 311031319993 is a prime.
It is not an unprimeable number, because it can be changed into a prime (311031320009) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51838553331 + ... + 51838553336.
It is an arithmetic number, because the mean of its divisors is an integer number (103677106668).
Almost surely, 2311031320001 is an apocalyptic number.
It is an amenable number.
311031320001 is a deficient number, since it is larger than the sum of its proper divisors (103677106671).
311031320001 is a wasteful number, since it uses less digits than its factorization.
311031320001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 103677106670.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 311031320001 its reverse (100023130113), we get a palindrome (411054450114).
The spelling of 311031320001 in words is "three hundred eleven billion, thirty-one million, three hundred twenty thousand, one".
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