Base | Representation |
---|---|
bin | 1110001001001110000111… |
… | …10111100011100101011011 |
3 | 11002010102122121100002012200 |
4 | 13010213003313203211123 |
5 | 13034043214420424011 |
6 | 150052330502141243 |
7 | 6360061624333464 |
oct | 704470367434533 |
9 | 132112577302180 |
10 | 31103144311131 |
11 | 9a01851119592 |
12 | 35a3bb8121823 |
13 | 1448024788449 |
14 | 7975862a3d6b |
15 | 38e0e6827856 |
hex | 1c49c3de395b |
31103144311131 has 12 divisors (see below), whose sum is σ = 44940012873600. Its totient is φ = 20729314678320.
The previous prime is 31103144311123. The next prime is 31103144311139. The reversal of 31103144311131 is 13111344130113.
31103144311131 is a `hidden beast` number, since 3 + 1 + 1 + 0 + 314 + 4 + 311 + 1 + 31 = 666.
It is an interprime number because it is at equal distance from previous prime (31103144311123) and next prime (31103144311139).
It is not a de Polignac number, because 31103144311131 - 23 = 31103144311123 is a prime.
It is a super-2 number, since 2×311031443111312 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 31103144311095 and 31103144311104.
It is not an unprimeable number, because it can be changed into a prime (31103144311139) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 509539656 + ... + 509600693.
It is an arithmetic number, because the mean of its divisors is an integer number (3745001072800).
Almost surely, 231103144311131 is an apocalyptic number.
31103144311131 is a deficient number, since it is larger than the sum of its proper divisors (13836868562469).
31103144311131 is a wasteful number, since it uses less digits than its factorization.
31103144311131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1019143746 (or 1019143743 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 27.
Adding to 31103144311131 its reverse (13111344130113), we get a palindrome (44214488441244).
The spelling of 31103144311131 in words is "thirty-one trillion, one hundred three billion, one hundred forty-four million, three hundred eleven thousand, one hundred thirty-one".
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