Base | Representation |
---|---|
bin | 11100111101111101… |
… | …110111110000110001 |
3 | 2222021201102020221212 |
4 | 130331331313300301 |
5 | 1002200211303213 |
6 | 22142243125505 |
7 | 2150540020121 |
oct | 347575676061 |
9 | 88251366855 |
10 | 31104400433 |
11 | 12211694467 |
12 | 6040973895 |
13 | 2c19126992 |
14 | 1710db0c81 |
15 | c20a7d9a8 |
hex | 73df77c31 |
31104400433 has 8 divisors (see below), whose sum is σ = 33540047520. Its totient is φ = 28748610720.
The previous prime is 31104400367. The next prime is 31104400447. The reversal of 31104400433 is 33400440113.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 31104400433 - 210 = 31104399409 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 31104400399 and 31104400408.
It is not an unprimeable number, because it can be changed into a prime (31104400133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 19963535 + ... + 19965092.
It is an arithmetic number, because the mean of its divisors is an integer number (4192505940).
Almost surely, 231104400433 is an apocalyptic number.
It is an amenable number.
31104400433 is a deficient number, since it is larger than the sum of its proper divisors (2435647087).
31104400433 is a wasteful number, since it uses less digits than its factorization.
31104400433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 39928687.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 31104400433 its reverse (33400440113), we get a palindrome (64504840546).
The spelling of 31104400433 in words is "thirty-one billion, one hundred four million, four hundred thousand, four hundred thirty-three".
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