311100112313 has 4 divisors (see below), whose sum is σ = 311143214160. Its totient is φ = 311057010468.

The previous prime is 311100112303. The next prime is 311100112321. The reversal of 311100112313 is 313211001113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 313211001113 = 2689 ⋅116478617.

It is a cyclic number.

It is not a de Polignac number, because 311100112313 - 2⁶ = 311100112249 is a prime.

It is a super-2 number, since 2×311100112313² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 311100112291 and 311100112300.

It is not an unprimeable number, because it can be changed into a prime (311100112303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21540095 + ... + 21554532.

It is an arithmetic number, because the mean of its divisors is an integer number (77785803540).

Almost surely, 2^311100112313 is an apocalyptic number.

It is an amenable number.

311100112313 is a deficient number, since it is larger than the sum of its proper divisors (43101847).

311100112313 is an equidigital number, since it uses as much as digits as its factorization.

311100112313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43101846.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 311100112313 its reverse (313211001113), we get a palindrome (624311113426).

The spelling of 311100112313 in words is "three hundred eleven billion, one hundred million, one hundred twelve thousand, three hundred thirteen".