Base | Representation |
---|---|
bin | 101101010001011100000… |
… | …100011111000110000001 |
3 | 102000102021222101221210020 |
4 | 231101130010133012001 |
5 | 401433013324031423 |
6 | 10341115311324053 |
7 | 440524661123166 |
oct | 55213404370601 |
9 | 12012258357706 |
10 | 3111101002113 |
11 | a9a457455a95 |
12 | 422b51520629 |
13 | 1974b616b940 |
14 | aa8143da06d |
15 | 55dd831e4e3 |
hex | 2d45c11f181 |
3111101002113 has 8 divisors (see below), whose sum is σ = 4467221951808. Its totient is φ = 1914523693584.
The previous prime is 3111101002109. The next prime is 3111101002123. The reversal of 3111101002113 is 3112001011113.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 3111101002113 - 22 = 3111101002109 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3111101002092 and 3111101002101.
It is not an unprimeable number, because it can be changed into a prime (3111101002123) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 39885910245 + ... + 39885910322.
It is an arithmetic number, because the mean of its divisors is an integer number (558402743976).
Almost surely, 23111101002113 is an apocalyptic number.
It is an amenable number.
3111101002113 is a deficient number, since it is larger than the sum of its proper divisors (1356120949695).
3111101002113 is a wasteful number, since it uses less digits than its factorization.
3111101002113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 79771820583.
The product of its (nonzero) digits is 18, while the sum is 15.
Adding to 3111101002113 its reverse (3112001011113), we get a palindrome (6223102013226).
The spelling of 3111101002113 in words is "three trillion, one hundred eleven billion, one hundred one million, two thousand, one hundred thirteen".
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