Base | Representation |
---|---|
bin | 101101010001100010101… |
… | …100010111110000011001 |
3 | 102000102120201111101101202 |
4 | 231101202230113300121 |
5 | 401433230300333423 |
6 | 10341134321123545 |
7 | 440530510455245 |
oct | 55214254276031 |
9 | 12012521441352 |
10 | 3111212121113 |
11 | a9a504151378 |
12 | 422b827895b5 |
13 | 1975031a6425 |
14 | aa825083425 |
15 | 55de2e6d728 |
hex | 2d462b17c19 |
3111212121113 has 4 divisors (see below), whose sum is σ = 3112580892468. Its totient is φ = 3109843349760.
The previous prime is 3111212121097. The next prime is 3111212121161.
3111212121113 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 2942912802064 + 168299319049 = 1715492^2 + 410243^2 .
It is a cyclic number.
It is not a de Polignac number, because 3111212121113 - 24 = 3111212121097 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3111212120113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 684382268 + ... + 684386813.
It is an arithmetic number, because the mean of its divisors is an integer number (778145223117).
Almost surely, 23111212121113 is an apocalyptic number.
It is an amenable number.
3111212121113 is a deficient number, since it is larger than the sum of its proper divisors (1368771355).
3111212121113 is a wasteful number, since it uses less digits than its factorization.
3111212121113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1368771354.
The product of its digits is 72, while the sum is 20.
The spelling of 3111212121113 in words is "three trillion, one hundred eleven billion, two hundred twelve million, one hundred twenty-one thousand, one hundred thirteen".
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