Base | Representation |
---|---|
bin | 1110001001011111000000… |
… | …10010101100001110001001 |
3 | 11002011022001111010202011211 |
4 | 13010233200102230032021 |
5 | 13034220302021333113 |
6 | 150100430311253121 |
7 | 6360532411053550 |
oct | 704574022541611 |
9 | 132138044122154 |
10 | 31112211121033 |
11 | 9a056840a2009 |
12 | 35a590867a1a1 |
13 | 1448b3b02b213 |
14 | 797ba650ad97 |
15 | 38e4777eeb3d |
hex | 1c4be04ac389 |
31112211121033 has 8 divisors (see below), whose sum is σ = 35562942184320. Its totient is φ = 26663012426400.
The previous prime is 31112211121009. The next prime is 31112211121049. The reversal of 31112211121033 is 33012111221113.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 31112211121033 - 25 = 31112211121001 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 31112211120995 and 31112211121013.
It is not an unprimeable number, because it can be changed into a prime (31112211121333) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 383048653 + ... + 383129866.
It is an arithmetic number, because the mean of its divisors is an integer number (4445367773040).
Almost surely, 231112211121033 is an apocalyptic number.
It is an amenable number.
31112211121033 is a deficient number, since it is larger than the sum of its proper divisors (4450731063287).
31112211121033 is an equidigital number, since it uses as much as digits as its factorization.
31112211121033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 766184327.
The product of its (nonzero) digits is 216, while the sum is 22.
Adding to 31112211121033 its reverse (33012111221113), we get a palindrome (64124322342146).
The spelling of 31112211121033 in words is "thirty-one trillion, one hundred twelve billion, two hundred eleven million, one hundred twenty-one thousand, thirty-three".
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