Base | Representation |
---|---|
bin | 1001000011100001101… |
… | …11000101010010111001 |
3 | 1002202002021010011210111 |
4 | 10201300313011102321 |
5 | 20044144032224423 |
6 | 354533123544321 |
7 | 31323055665433 |
oct | 4416067052271 |
9 | 1082067104714 |
10 | 311131133113 |
11 | 10aa4a460369 |
12 | 5037122b0a1 |
13 | 23454c7a6c8 |
14 | 110b75c9653 |
15 | 815ea0260d |
hex | 4870dc54b9 |
311131133113 has 4 divisors (see below), whose sum is σ = 311132901520. Its totient is φ = 311129364708.
The previous prime is 311131133107. The next prime is 311131133189. The reversal of 311131133113 is 311331131113.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311331131113 = 129953 ⋅2395721.
It is a cyclic number.
It is not a de Polignac number, because 311131133113 - 213 = 311131124921 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (311131133213) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 586995 + ... + 983272.
It is an arithmetic number, because the mean of its divisors is an integer number (77783225380).
Almost surely, 2311131133113 is an apocalyptic number.
It is an amenable number.
311131133113 is a deficient number, since it is larger than the sum of its proper divisors (1768407).
311131133113 is a wasteful number, since it uses less digits than its factorization.
311131133113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1768406.
The product of its digits is 243, while the sum is 22.
Adding to 311131133113 its reverse (311331131113), we get a palindrome (622462264226).
The spelling of 311131133113 in words is "three hundred eleven billion, one hundred thirty-one million, one hundred thirty-three thousand, one hundred thirteen".
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