31113200103121 has 4 divisors (see below), whose sum is σ = 31113234812272. Its totient is φ = 31113165393972.

The previous prime is 31113200103091. The next prime is 31113200103163. The reversal of 31113200103121 is 12130100231113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-31113200103121 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (31113200103191) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15973335 + ... + 17814988.

It is an arithmetic number, because the mean of its divisors is an integer number (7778308703068).

Almost surely, 2^{31113200103121} is an apocalyptic number.

It is an amenable number.

31113200103121 is a deficient number, since it is larger than the sum of its proper divisors (34709151).

31113200103121 is an equidigital number, since it uses as much as digits as its factorization.

31113200103121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34709150.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 31113200103121 its reverse (12130100231113), we get a palindrome (43243300334234).

The spelling of 31113200103121 in words is "thirty-one trillion, one hundred thirteen billion, two hundred million, one hundred three thousand, one hundred twenty-one".