Base | Representation |
---|---|
bin | 100011010111110010010010… |
… | …0000101001001110000100001 |
3 | 1111210121221221010010202102212 |
4 | 1012233210210011021300201 |
5 | 311240043003243020001 |
6 | 3021420115245051505 |
7 | 122351366132531504 |
oct | 10657444405116041 |
9 | 1453557833122385 |
10 | 311132331220001 |
11 | 90155531852665 |
12 | 2aa8b644256b95 |
13 | 1047b864686bc5 |
14 | 56b8c56d1113b |
15 | 25e83ec8687bb |
hex | 11af924149c21 |
311132331220001 has 8 divisors (see below), whose sum is σ = 311146955764224. Its totient is φ = 311117707103760.
The previous prime is 311132331219971. The next prime is 311132331220003. The reversal of 311132331220001 is 100022133231113.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 311132331220001 - 242 = 306734284708897 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (311132331220003) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3571961216 + ... + 3572048318.
It is an arithmetic number, because the mean of its divisors is an integer number (38893369470528).
Almost surely, 2311132331220001 is an apocalyptic number.
It is an amenable number.
311132331220001 is a deficient number, since it is larger than the sum of its proper divisors (14624544223).
311132331220001 is an equidigital number, since it uses as much as digits as its factorization.
311132331220001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 213991.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 311132331220001 its reverse (100022133231113), we get a palindrome (411154464451114).
The spelling of 311132331220001 in words is "three hundred eleven trillion, one hundred thirty-two billion, three hundred thirty-one million, two hundred twenty thousand, one".
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