Base | Representation |
---|---|
bin | 1110001001100001000111… |
… | …11010011001011010000001 |
3 | 11002011101222112212102010220 |
4 | 13010300203322121122001 |
5 | 13034230112433300301 |
6 | 150101135035213253 |
7 | 6360602465024001 |
oct | 704604372313201 |
9 | 132141875772126 |
10 | 31113345603201 |
11 | 9a06106519284 |
12 | 35a5b845a7229 |
13 | 1448c8c093044 |
14 | 797c73064001 |
15 | 38e4e21e7936 |
hex | 1c4c23e99681 |
31113345603201 has 8 divisors (see below), whose sum is σ = 41484501852864. Its totient is φ = 20742209877840.
The previous prime is 31113345603199. The next prime is 31113345603253. The reversal of 31113345603201 is 10230654331113.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 31113345603201 - 21 = 31113345603199 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (31113345603271) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1153405 + ... + 7972266.
It is an arithmetic number, because the mean of its divisors is an integer number (5185562731608).
Almost surely, 231113345603201 is an apocalyptic number.
It is an amenable number.
31113345603201 is a deficient number, since it is larger than the sum of its proper divisors (10371156249663).
31113345603201 is a wasteful number, since it uses less digits than its factorization.
31113345603201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10262151.
The product of its (nonzero) digits is 19440, while the sum is 33.
Adding to 31113345603201 its reverse (10230654331113), we get a palindrome (41343999934314).
The spelling of 31113345603201 in words is "thirty-one trillion, one hundred thirteen billion, three hundred forty-five million, six hundred three thousand, two hundred one".
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