Base | Representation |
---|---|
bin | 101101010001110001010… |
… | …000110000100110111001 |
3 | 102000110012202102012121100 |
4 | 231101301100300212321 |
5 | 401434230333303423 |
6 | 10341214452002013 |
7 | 440536536140064 |
oct | 55216120604671 |
9 | 12013182365540 |
10 | 3111456541113 |
11 | a9a61a113778 |
12 | 423030600309 |
13 | 197541a1404b |
14 | aa8497098db |
15 | 55e0964e343 |
hex | 2d4714309b9 |
3111456541113 has 6 divisors (see below), whose sum is σ = 4494326114954. Its totient is φ = 2074304360736.
The previous prime is 3111456541013. The next prime is 3111456541139.
3111456541113 is a `hidden beast` number, since 31 + 1 + 14 + 565 + 41 + 1 + 13 = 666.
3111456541113 is nontrivially palindromic in base 10.
It can be written as a sum of positive squares in only one way, i.e., 3077087830569 + 34368710544 = 1754163^2 + 185388^2 .
It is not a de Polignac number, because 3111456541113 - 224 = 3111439763897 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3111456541183) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 172858696720 + ... + 172858696737.
Almost surely, 23111456541113 is an apocalyptic number.
It is an amenable number.
3111456541113 is a deficient number, since it is larger than the sum of its proper divisors (1382869573841).
3111456541113 is a wasteful number, since it uses less digits than its factorization.
3111456541113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 345717393463 (or 345717393460 counting only the distinct ones).
The product of its digits is 21600, while the sum is 36.
The spelling of 3111456541113 in words is "three trillion, one hundred eleven billion, four hundred fifty-six million, five hundred forty-one thousand, one hundred thirteen".
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