311204947 has 4 divisors (see below), whose sum is σ = 311361256. Its totient is φ = 311048640.

The previous prime is 311204911. The next prime is 311204951. The reversal of 311204947 is 749402113.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 749402113 = 2309 ⋅324557.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-311204947 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (311204977) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 75129 + ... + 79162.

It is an arithmetic number, because the mean of its divisors is an integer number (77840314).

Almost surely, 2^311204947 is an apocalyptic number.

311204947 is a deficient number, since it is larger than the sum of its proper divisors (156309).

311204947 is a wasteful number, since it uses less digits than its factorization.

311204947 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 156308.

The product of its (nonzero) digits is 6048, while the sum is 31.

The square root of 311204947 is about 17641.0018706422. The cubic root of 311204947 is about 677.6656889731.

The spelling of 311204947 in words is "three hundred eleven million, two hundred four thousand, nine hundred forty-seven".