Base | Representation |
---|---|
bin | 1110001001101111110001… |
… | …10110100110100110111011 |
3 | 11002012011021211222211101012 |
4 | 13010313320312212212323 |
5 | 13034342221024414003 |
6 | 150104515443344135 |
7 | 6361301446603343 |
oct | 704677066464673 |
9 | 132164254884335 |
10 | 31121213123003 |
11 | 9a09483530363 |
12 | 35a75bb38204b |
13 | 144994402c7c3 |
14 | 7983bbcc3d23 |
15 | 38e802c748d8 |
hex | 1c4df8da69bb |
31121213123003 has 4 divisors (see below), whose sum is σ = 31121266186560. Its totient is φ = 31121160059448.
The previous prime is 31121213122981. The next prime is 31121213123047. The reversal of 31121213123003 is 30032131212113.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 31121213123003 - 244 = 13529027078587 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 31121213123003.
It is not an unprimeable number, because it can be changed into a prime (31121213123053) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25642100 + ... + 26828337.
It is an arithmetic number, because the mean of its divisors is an integer number (7780316546640).
Almost surely, 231121213123003 is an apocalyptic number.
31121213123003 is a deficient number, since it is larger than the sum of its proper divisors (53063557).
31121213123003 is an equidigital number, since it uses as much as digits as its factorization.
31121213123003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 53063556.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 31121213123003 its reverse (30032131212113), we get a palindrome (61153344335116).
The spelling of 31121213123003 in words is "thirty-one trillion, one hundred twenty-one billion, two hundred thirteen million, one hundred twenty-three thousand, three".
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