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31122013001 = 124372502373
BaseRepresentation
bin11100111111000001…
…000011101101001001
32222022221120001212012
4130333001003231021
51002214213404001
622144112425305
72151142513532
oct347701035511
988287501765
1031122013001
1112220624002
126046848235
132c1c982511
141713477689
15c223ac2bb
hex73f043b49

31122013001 has 4 divisors (see below), whose sum is σ = 31124527812. Its totient is φ = 31119498192.

The previous prime is 31122012997. The next prime is 31122013003. The reversal of 31122013001 is 10031022113.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 11566787401 + 19555225600 = 107549^2 + 139840^2 .

It is a cyclic number.

It is not a de Polignac number, because 31122013001 - 22 = 31122012997 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (31122013003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1238750 + ... + 1263623.

It is an arithmetic number, because the mean of its divisors is an integer number (7781131953).

Almost surely, 231122013001 is an apocalyptic number.

It is an amenable number.

31122013001 is a deficient number, since it is larger than the sum of its proper divisors (2514811).

31122013001 is a wasteful number, since it uses less digits than its factorization.

31122013001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2514810.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 31122013001 its reverse (10031022113), we get a palindrome (41153035114).

The spelling of 31122013001 in words is "thirty-one billion, one hundred twenty-two million, thirteen thousand, one".

Divisors: 1 12437 2502373 31122013001