Base | Representation |
---|---|
bin | 11100111111000001… |
… | …110010000111111011 |
3 | 2222022221220201200001 |
4 | 130333001302013323 |
5 | 1002214241000011 |
6 | 22144120453431 |
7 | 2151144235045 |
oct | 347701620773 |
9 | 88287821601 |
10 | 31122203131 |
11 | 12220743938 |
12 | 604691a277 |
13 | 2c1ca1ac16 |
14 | 17134c6a95 |
15 | c223e87c1 |
hex | 73f0721fb |
31122203131 has 4 divisors (see below), whose sum is σ = 31123827832. Its totient is φ = 31120578432.
The previous prime is 31122203117. The next prime is 31122203137. The reversal of 31122203131 is 13130222113.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 31122203131 - 221 = 31120105979 is a prime.
It is a super-2 number, since 2×311222031312 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 31122203099 and 31122203108.
It is not an unprimeable number, because it can be changed into a prime (31122203137) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 783270 + ... + 822043.
It is an arithmetic number, because the mean of its divisors is an integer number (7780956958).
Almost surely, 231122203131 is an apocalyptic number.
31122203131 is a deficient number, since it is larger than the sum of its proper divisors (1624701).
31122203131 is a wasteful number, since it uses less digits than its factorization.
31122203131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1624700.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 31122203131 its reverse (13130222113), we get a palindrome (44252425244).
The spelling of 31122203131 in words is "thirty-one billion, one hundred twenty-two million, two hundred three thousand, one hundred thirty-one".
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