311230011331 has 4 divisors (see below), whose sum is σ = 312211809792. Its totient is φ = 310248212872.

The previous prime is 311230011311. The next prime is 311230011341. The reversal of 311230011331 is 133110032113.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 311230011331 - 2¹⁷ = 311229880259 is a prime.

It is a super-3 number, since 3×311230011331³ (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 311230011299 and 311230011308.

It is not an unprimeable number, because it can be changed into a prime (311230011311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 490898755 + ... + 490899388.

It is an arithmetic number, because the mean of its divisors is an integer number (78052952448).

Almost surely, 2^311230011331 is an apocalyptic number.

311230011331 is a deficient number, since it is larger than the sum of its proper divisors (981798461).

311230011331 is an equidigital number, since it uses as much as digits as its factorization.

311230011331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 981798460.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 311230011331 its reverse (133110032113), we get a palindrome (444340043444).

The spelling of 311230011331 in words is "three hundred eleven billion, two hundred thirty million, eleven thousand, three hundred thirty-one".