3113001202001 has 4 divisors (see below), whose sum is σ = 3113216217600. Its totient is φ = 3112786186404.

The previous prime is 3113001201991. The next prime is 3113001202093. The reversal of 3113001202001 is 1002021003113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3113001202001 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (3113001202501) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 107486081 + ... + 107515038.

It is an arithmetic number, because the mean of its divisors is an integer number (778304054400).

Almost surely, 2^{3113001202001} is an apocalyptic number.

It is an amenable number.

3113001202001 is a deficient number, since it is larger than the sum of its proper divisors (215015599).

3113001202001 is a wasteful number, since it uses less digits than its factorization.

3113001202001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 215015598.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 3113001202001 its reverse (1002021003113), we get a palindrome (4115022205114).

The spelling of 3113001202001 in words is "three trillion, one hundred thirteen billion, one million, two hundred two thousand, one".