Base | Representation |
---|---|
bin | 101101010011001101010… |
… | …101100110011101001011 |
3 | 102000121012102011210210112 |
4 | 231103031111212131023 |
5 | 402000411314022443 |
6 | 10342032033504535 |
7 | 440623034402351 |
oct | 55231525463513 |
9 | 12017172153715 |
10 | 3113001314123 |
11 | aa02420a4588 |
12 | 4233a1a1214b |
13 | 197729a8150c |
14 | aa9549457d1 |
15 | 55e9a08eb18 |
hex | 2d4cd56674b |
3113001314123 has 4 divisors (see below), whose sum is σ = 3118472318760. Its totient is φ = 3107530309488.
The previous prime is 3113001314119. The next prime is 3113001314153. The reversal of 3113001314123 is 3214131003113.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3113001314123 - 22 = 3113001314119 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3113001314153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2735501465 + ... + 2735502602.
It is an arithmetic number, because the mean of its divisors is an integer number (779618079690).
Almost surely, 23113001314123 is an apocalyptic number.
3113001314123 is a deficient number, since it is larger than the sum of its proper divisors (5471004637).
3113001314123 is an equidigital number, since it uses as much as digits as its factorization.
3113001314123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5471004636.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 3113001314123 its reverse (3214131003113), we get a palindrome (6327132317236).
The spelling of 3113001314123 in words is "three trillion, one hundred thirteen billion, one million, three hundred fourteen thousand, one hundred twenty-three".
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