311311222113113 has 4 divisors (see below), whose sum is σ = 311604083094528. Its totient is φ = 311018361131700.

The previous prime is 311311222113037. The next prime is 311311222113127.

311311222113113 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 311311222113113 - 2¹⁶ = 311311222047577 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (311311222113193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 146430489113 + ... + 146430491238.

It is an arithmetic number, because the mean of its divisors is an integer number (77901020773632).

Almost surely, 2^{311311222113113} is an apocalyptic number.

It is an amenable number.

311311222113113 is a deficient number, since it is larger than the sum of its proper divisors (292860981415).

311311222113113 is a wasteful number, since it uses less digits than its factorization.

311311222113113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 292860981414.

The product of its digits is 648, while the sum is 26.

The spelling of 311311222113113 in words is "three hundred eleven trillion, three hundred eleven billion, two hundred twenty-two million, one hundred thirteen thousand, one hundred thirteen".