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311311233113 = 551175648189
BaseRepresentation
bin1001000011110111001…
…10000111000001011001
31002202112211000012112212
410201323212013001121
520100031133424423
6355003040044505
731330403551346
oct4417346070131
91082484005485
10311311233113
11110032091141
1250401603735
1323483387c5a
14110d34ab7cd
15817072a578
hex487b987059

311311233113 has 4 divisors (see below), whose sum is σ = 311316936420. Its totient is φ = 311305529808.

The previous prime is 311311233097. The next prime is 311311233157. The reversal of 311311233113 is 311332113113.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 170628477184 + 140682755929 = 413072^2 + 375077^2 .

It is a cyclic number.

It is not a de Polignac number, because 311311233113 - 24 = 311311233097 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (311311238113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2768978 + ... + 2879211.

It is an arithmetic number, because the mean of its divisors is an integer number (77829234105).

Almost surely, 2311311233113 is an apocalyptic number.

It is an amenable number.

311311233113 is a deficient number, since it is larger than the sum of its proper divisors (5703307).

311311233113 is an equidigital number, since it uses as much as digits as its factorization.

311311233113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5703306.

The product of its digits is 486, while the sum is 23.

Adding to 311311233113 its reverse (311332113113), we get a palindrome (622643346226).

The spelling of 311311233113 in words is "three hundred eleven billion, three hundred eleven million, two hundred thirty-three thousand, one hundred thirteen".

Divisors: 1 55117 5648189 311311233113