Base | Representation |
---|---|
bin | 1110001010000010011000… |
… | …11100001101100100011011 |
3 | 11002020010002020021101102110 |
4 | 13011001030130031210123 |
5 | 13040023202042103220 |
6 | 150113251153203403 |
7 | 6362104202015403 |
oct | 705011434154433 |
9 | 132203066241373 |
10 | 31131205425435 |
11 | 9a12740968045 |
12 | 35a9529860563 |
13 | 144a8772533ab |
14 | 798a89001803 |
15 | 38ebda111be0 |
hex | 1c504c70d91b |
31131205425435 has 16 divisors (see below), whose sum is σ = 49810000341024. Its totient is φ = 16603285673472.
The previous prime is 31131205425367. The next prime is 31131205425443. The reversal of 31131205425435 is 53452450213113.
It is not a de Polignac number, because 31131205425435 - 28 = 31131205425179 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 31131205425393 and 31131205425402.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 15576499 + ... + 17461091.
It is an arithmetic number, because the mean of its divisors is an integer number (3113125021314).
Almost surely, 231131205425435 is an apocalyptic number.
31131205425435 is a deficient number, since it is larger than the sum of its proper divisors (18678794915589).
31131205425435 is a wasteful number, since it uses less digits than its factorization.
31131205425435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2985854.
The product of its (nonzero) digits is 216000, while the sum is 39.
Adding to 31131205425435 its reverse (53452450213113), we get a palindrome (84583655638548).
The spelling of 31131205425435 in words is "thirty-one trillion, one hundred thirty-one billion, two hundred five million, four hundred twenty-five thousand, four hundred thirty-five".
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