3113122201331 has 4 divisors (see below), whose sum is σ = 3113134848000. Its totient is φ = 3113109554664.

The previous prime is 3113122201291. The next prime is 3113122201333. The reversal of 3113122201331 is 1331022213113.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3113122201331 is a prime.

It is a super-2 number, since 2×3113122201331² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3113122201297 and 3113122201306.

It is not an unprimeable number, because it can be changed into a prime (3113122201333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5946611 + ... + 6448908.

It is an arithmetic number, because the mean of its divisors is an integer number (778283712000).

Almost surely, 2^{3113122201331} is an apocalyptic number.

3113122201331 is a deficient number, since it is larger than the sum of its proper divisors (12646669).

3113122201331 is a wasteful number, since it uses less digits than its factorization.

3113122201331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12646668.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 3113122201331 its reverse (1331022213113), we get a palindrome (4444144414444).

The spelling of 3113122201331 in words is "three trillion, one hundred thirteen billion, one hundred twenty-two million, two hundred one thousand, three hundred thirty-one".