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311313112001 = 3111001006791
BaseRepresentation
bin1001000011110111011…
…01010001101111000001
31002202112221112122220022
410201323231101233001
520100032124041001
6355003144223225
731330425535223
oct4417355215701
91082487478808
10311313112001
11110033154841
125040216ab15
1323483895218
14110d383a413
15817099c11b
hex487bb51bc1

311313112001 has 4 divisors (see below), whose sum is σ = 312314119104. Its totient is φ = 310312104900.

The previous prime is 311313111973. The next prime is 311313112009. The reversal of 311313112001 is 100211313113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-311313112001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (311313112009) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 500503085 + ... + 500503706.

It is an arithmetic number, because the mean of its divisors is an integer number (78078529776).

Almost surely, 2311313112001 is an apocalyptic number.

It is an amenable number.

311313112001 is a deficient number, since it is larger than the sum of its proper divisors (1001007103).

311313112001 is a wasteful number, since it uses less digits than its factorization.

311313112001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1001007102.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 311313112001 its reverse (100211313113), we get a palindrome (411524425114).

The spelling of 311313112001 in words is "three hundred eleven billion, three hundred thirteen million, one hundred twelve thousand, one".

Divisors: 1 311 1001006791 311313112001