Base | Representation |
---|---|
bin | 1110001010000011110111… |
… | …11011010111001010000011 |
3 | 11002020012010202101200100112 |
4 | 13011001323323113022003 |
5 | 13040031320020322243 |
6 | 150113502213141535 |
7 | 6362133014555126 |
oct | 705017373271203 |
9 | 132205122350315 |
10 | 31132002120323 |
11 | 9a1300a650775 |
12 | 35a971062a8ab |
13 | 144a973319aa0 |
14 | 798b22b4a3bd |
15 | 38ec35034818 |
hex | 1c507bed7283 |
31132002120323 has 8 divisors (see below), whose sum is σ = 33526868046000. Its totient is φ = 28737149984928.
The previous prime is 31132002120283. The next prime is 31132002120361. The reversal of 31132002120323 is 32302120023113.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 31132002120323 - 216 = 31132002054787 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (31132002120223) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1504628 + ... + 8032926.
It is an arithmetic number, because the mean of its divisors is an integer number (4190858505750).
Almost surely, 231132002120323 is an apocalyptic number.
31132002120323 is a deficient number, since it is larger than the sum of its proper divisors (2394865925677).
31132002120323 is a wasteful number, since it uses less digits than its factorization.
31132002120323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6895141.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 31132002120323 its reverse (32302120023113), we get a palindrome (63434122143436).
The spelling of 31132002120323 in words is "thirty-one trillion, one hundred thirty-two billion, two million, one hundred twenty thousand, three hundred twenty-three".
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