Base | Representation |
---|---|
bin | 101101010011011001011… |
… | …011111110111110010001 |
3 | 102000121201120011021021112 |
4 | 231103121123332332101 |
5 | 402001320301022001 |
6 | 10342104124503105 |
7 | 440631051022625 |
oct | 55233133767621 |
9 | 12017646137245 |
10 | 3113204314001 |
11 | aa0336746381 |
12 | 4234399aaa95 |
13 | 19775cb490a2 |
14 | aa9738a9185 |
15 | 55eaccdccbb |
hex | 2d4d96fef91 |
3113204314001 has 8 divisors (see below), whose sum is σ = 3120903895200. Its totient is φ = 3105505162080.
The previous prime is 3113204313971. The next prime is 3113204314009. The reversal of 3113204314001 is 1004134023113.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 3113204314001 - 218 = 3113204051857 is a prime.
It is a super-2 number, since 2×31132043140012 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3113204314009) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 18308510 + ... + 18477768.
It is an arithmetic number, because the mean of its divisors is an integer number (390112986900).
Almost surely, 23113204314001 is an apocalyptic number.
It is an amenable number.
3113204314001 is a deficient number, since it is larger than the sum of its proper divisors (7699581199).
3113204314001 is a wasteful number, since it uses less digits than its factorization.
3113204314001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 214639.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 3113204314001 its reverse (1004134023113), we get a palindrome (4117338337114).
The spelling of 3113204314001 in words is "three trillion, one hundred thirteen billion, two hundred four million, three hundred fourteen thousand, one".
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