311321131331 has 4 divisors (see below), whose sum is σ = 355795578672. Its totient is φ = 266846683992.

The previous prime is 311321131321. The next prime is 311321131343. The reversal of 311321131331 is 133131123113.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 133131123113 = 347 ⋅383663179.

It is not a de Polignac number, because 311321131331 - 2¹⁸ = 311320869187 is a prime.

It is a super-2 number, since 2×311321131331² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 311321131297 and 311321131306.

It is not an unprimeable number, because it can be changed into a prime (311321131321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22237223660 + ... + 22237223673.

It is an arithmetic number, because the mean of its divisors is an integer number (88948894668).

Almost surely, 2^311321131331 is an apocalyptic number.

311321131331 is a deficient number, since it is larger than the sum of its proper divisors (44474447341).

311321131331 is an equidigital number, since it uses as much as digits as its factorization.

311321131331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 44474447340.

The product of its digits is 486, while the sum is 23.

Adding to 311321131331 its reverse (133131123113), we get a palindrome (444452254444).

The spelling of 311321131331 in words is "three hundred eleven billion, three hundred twenty-one million, one hundred thirty-one thousand, three hundred thirty-one".