3113214123113 has 4 divisors (see below), whose sum is σ = 3113250796800. Its totient is φ = 3113177449428.

The previous prime is 3113214123091. The next prime is 3113214123133.

3113214123113 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3113214123113 - 2¹⁴ = 3113214106729 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3113214123133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18209213 + ... + 18379386.

It is an arithmetic number, because the mean of its divisors is an integer number (778312699200).

Almost surely, 2^{3113214123113} is an apocalyptic number.

It is an amenable number.

3113214123113 is a deficient number, since it is larger than the sum of its proper divisors (36673687).

3113214123113 is an equidigital number, since it uses as much as digits as its factorization.

3113214123113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36673686.

The product of its digits is 1296, while the sum is 26.

The spelling of 3113214123113 in words is "three trillion, one hundred thirteen billion, two hundred fourteen million, one hundred twenty-three thousand, one hundred thirteen".