Base | Representation |
---|---|
bin | 1110001010000100101100… |
… | …01110011111111000010011 |
3 | 11002020020021111122012000010 |
4 | 13011002112032133320103 |
5 | 13040033220444010103 |
6 | 150114014054130003 |
7 | 6362146653113532 |
oct | 705022616377023 |
9 | 132206244565003 |
10 | 31132443344403 |
11 | 9a13216712975 |
12 | 35a9814350903 |
13 | 144aa1386311b |
14 | 798b655a2319 |
15 | 38ec5db3c903 |
hex | 1c509639fe13 |
31132443344403 has 8 divisors (see below), whose sum is σ = 41554037028816. Its totient is φ = 20732905944800.
The previous prime is 31132443344389. The next prime is 31132443344449. The reversal of 31132443344403 is 30444334423113.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 31132443344403 - 29 = 31132443343891 is a prime.
It is not an unprimeable number, because it can be changed into a prime (31132443344473) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5514067908 + ... + 5514073553.
It is an arithmetic number, because the mean of its divisors is an integer number (5194254628602).
Almost surely, 231132443344403 is an apocalyptic number.
31132443344403 is a deficient number, since it is larger than the sum of its proper divisors (10421593684413).
31132443344403 is a wasteful number, since it uses less digits than its factorization.
31132443344403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11028142405.
The product of its (nonzero) digits is 497664, while the sum is 39.
Adding to 31132443344403 its reverse (30444334423113), we get a palindrome (61576777767516).
The spelling of 31132443344403 in words is "thirty-one trillion, one hundred thirty-two billion, four hundred forty-three million, three hundred forty-four thousand, four hundred three".
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