311325252061451 has 4 divisors (see below), whose sum is σ = 311578567971600. Its totient is φ = 311071936151304.

The previous prime is 311325252061441. The next prime is 311325252061463. The reversal of 311325252061451 is 154160252523113.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 311325252061451 - 2¹⁸ = 311325251799307 is a prime.

It is a super-2 number, since 2×311325252061451² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 311325252061399 and 311325252061408.

It is not an unprimeable number, because it can be changed into a prime (311325252061441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 126657953231 + ... + 126657955688.

It is an arithmetic number, because the mean of its divisors is an integer number (77894641992900).

Almost surely, 2^{311325252061451} is an apocalyptic number.

311325252061451 is a deficient number, since it is larger than the sum of its proper divisors (253315910149).

311325252061451 is a wasteful number, since it uses less digits than its factorization.

311325252061451 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 253315910148.

The product of its (nonzero) digits is 216000, while the sum is 41.

The spelling of 311325252061451 in words is "three hundred eleven trillion, three hundred twenty-five billion, two hundred fifty-two million, sixty-one thousand, four hundred fifty-one".