3113300033113 has 4 divisors (see below), whose sum is σ = 3113304663988. Its totient is φ = 3113295402240.

The previous prime is 3113300033059. The next prime is 3113300033117.

3113300033113 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 665085918784 + 2448214114329 = 815528^2 + 1564677^2 .

It is a cyclic number.

It is not a de Polignac number, because 3113300033113 - 2¹³ = 3113300024921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3113300033117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1091256 + ... + 2723497.

It is an arithmetic number, because the mean of its divisors is an integer number (778326165997).

Almost surely, 2^{3113300033113} is an apocalyptic number.

It is an amenable number.

3113300033113 is a deficient number, since it is larger than the sum of its proper divisors (4630875).

3113300033113 is an equidigital number, since it uses as much as digits as its factorization.

3113300033113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4630874.

The product of its (nonzero) digits is 729, while the sum is 22.

It can be divided in two parts, 31133000 and 33113, that added together give a palindrome (31166113).

The spelling of 3113300033113 in words is "three trillion, one hundred thirteen billion, three hundred million, thirty-three thousand, one hundred thirteen".