Base | Representation |
---|---|
bin | 100011011001001110110101… |
… | …1101011101111000010011011 |
3 | 1111211022221222201120101222112 |
4 | 1012302131223223233002123 |
5 | 311301322043324341443 |
6 | 3022051311111342535 |
7 | 122401633625064563 |
oct | 10662355353570233 |
9 | 1454287881511875 |
10 | 311331101012123 |
11 | 90221862155435 |
12 | 2ab02077981a4b |
13 | 10494520b6610a |
14 | 56c471187bda3 |
15 | 25ed682cd6b18 |
hex | 11b276baef09b |
311331101012123 has 4 divisors (see below), whose sum is σ = 311331166378800. Its totient is φ = 311331035645448.
The previous prime is 311331101012117. The next prime is 311331101012153. The reversal of 311331101012123 is 321210101133113.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 311331101012123 - 238 = 311056223105179 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (311331101012153) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24925223 + ... + 35269376.
It is an arithmetic number, because the mean of its divisors is an integer number (77832791594700).
Almost surely, 2311331101012123 is an apocalyptic number.
311331101012123 is a deficient number, since it is larger than the sum of its proper divisors (65366677).
311331101012123 is an equidigital number, since it uses as much as digits as its factorization.
311331101012123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65366676.
The product of its (nonzero) digits is 324, while the sum is 23.
Adding to 311331101012123 its reverse (321210101133113), we get a palindrome (632541202145236).
The spelling of 311331101012123 in words is "three hundred eleven trillion, three hundred thirty-one billion, one hundred one million, twelve thousand, one hundred twenty-three".
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