311331431201 has 4 divisors (see below), whose sum is σ = 355807349952. Its totient is φ = 266855512452.

The previous prime is 311331431153. The next prime is 311331431207. The reversal of 311331431201 is 102134133113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 102134133113 = 6983 ⋅14626111.

It is a cyclic number.

It is not a de Polignac number, because 311331431201 - 2²² = 311327236897 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (311331431207) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22237959365 + ... + 22237959378.

It is an arithmetic number, because the mean of its divisors is an integer number (88951837488).

Almost surely, 2^311331431201 is an apocalyptic number.

It is an amenable number.

311331431201 is a deficient number, since it is larger than the sum of its proper divisors (44475918751).

311331431201 is an equidigital number, since it uses as much as digits as its factorization.

311331431201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44475918750.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 311331431201 its reverse (102134133113), we get a palindrome (413465564314).

The spelling of 311331431201 in words is "three hundred eleven billion, three hundred thirty-one million, four hundred thirty-one thousand, two hundred one".