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311332012001 = 513836059047
BaseRepresentation
bin1001000011111001101…
…01010111111111100001
31002202121021002212211022
410201330311113333201
520100101443341001
6355005101255225
731331045303243
oct4417465277741
91082537085738
10311332012001
1111004289367a
1250408564515
1323487781a5a
14110d615a093
15817248211b
hex487cd57fe1

311332012001 has 4 divisors (see below), whose sum is σ = 311338122432. Its totient is φ = 311325901572.

The previous prime is 311332011961. The next prime is 311332012031. The reversal of 311332012001 is 100210233113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-311332012001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (311332012031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2978141 + ... + 3080906.

It is an arithmetic number, because the mean of its divisors is an integer number (77834530608).

Almost surely, 2311332012001 is an apocalyptic number.

It is an amenable number.

311332012001 is a deficient number, since it is larger than the sum of its proper divisors (6110431).

311332012001 is an equidigital number, since it uses as much as digits as its factorization.

311332012001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6110430.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 311332012001 its reverse (100210233113), we get a palindrome (411542245114).

The spelling of 311332012001 in words is "three hundred eleven billion, three hundred thirty-two million, twelve thousand, one".

Divisors: 1 51383 6059047 311332012001