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31134333041 = 74447761863
BaseRepresentation
bin11100111111110000…
…000011100001110001
32222100210201222202222
4130333300003201301
51002230342124131
622145232450425
72151352315160
oct347760034161
988323658688
1031134333041
1112227579259
12604a9a9a15
132c223a7096
141714d633d7
15c234e287b
hex73fc03871

31134333041 has 4 divisors (see below), whose sum is σ = 35582094912. Its totient is φ = 26686571172.

The previous prime is 31134333031. The next prime is 31134333067. The reversal of 31134333041 is 14033343113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-31134333041 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 31134333041.

It is not an unprimeable number, because it can be changed into a prime (31134333011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2223880925 + ... + 2223880938.

It is an arithmetic number, because the mean of its divisors is an integer number (8895523728).

Almost surely, 231134333041 is an apocalyptic number.

It is an amenable number.

31134333041 is a deficient number, since it is larger than the sum of its proper divisors (4447761871).

31134333041 is an equidigital number, since it uses as much as digits as its factorization.

31134333041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4447761870.

The product of its (nonzero) digits is 3888, while the sum is 26.

Adding to 31134333041 its reverse (14033343113), we get a palindrome (45167676154).

The spelling of 31134333041 in words is "thirty-one billion, one hundred thirty-four million, three hundred thirty-three thousand, forty-one".

Divisors: 1 7 4447761863 31134333041