Base | Representation |
---|---|
bin | 1011100110011001… |
… | …1101010111111011 |
3 | 22001000021211011001 |
4 | 2321212131113323 |
5 | 22334122213442 |
6 | 1232552545431 |
7 | 140110300465 |
oct | 27146352773 |
9 | 8030254131 |
10 | 3113866747 |
11 | 13587731a2 |
12 | 72a9b2277 |
13 | 3a8171904 |
14 | 2177a7135 |
15 | 1335872b7 |
hex | b999d5fb |
3113866747 has 4 divisors (see below), whose sum is σ = 3114296680. Its totient is φ = 3113436816.
The previous prime is 3113866739. The next prime is 3113866807. The reversal of 3113866747 is 7476683113.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 7476683113 = 17 ⋅439804889.
It is a cyclic number.
It is not a de Polignac number, because 3113866747 - 23 = 3113866739 is a prime.
It is a super-2 number, since 2×31138667472 = 19392332236144724018, which contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3113866697 and 3113866706.
It is not an unprimeable number, because it can be changed into a prime (3113863747) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 203913 + ... + 218650.
It is an arithmetic number, because the mean of its divisors is an integer number (778574170).
Almost surely, 23113866747 is an apocalyptic number.
3113866747 is a deficient number, since it is larger than the sum of its proper divisors (429933).
3113866747 is an equidigital number, since it uses as much as digits as its factorization.
3113866747 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 429932.
The product of its digits is 508032, while the sum is 46.
The square root of 3113866747 is about 55802.0317461649. The cubic root of 3113866747 is about 1460.2705989648.
The spelling of 3113866747 in words is "three billion, one hundred thirteen million, eight hundred sixty-six thousand, seven hundred forty-seven".
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