Base | Representation |
---|---|
bin | 1110001010010010110010… |
… | …10010110101000011010001 |
3 | 11002020221210220112010112002 |
4 | 13011021121102311003101 |
5 | 13040144220304112423 |
6 | 150121305031243345 |
7 | 6362535334135424 |
oct | 705113122650321 |
9 | 132227726463462 |
10 | 31140011004113 |
11 | 9a1644a4366a0 |
12 | 35ab186819555 |
13 | 144b64b65068b |
14 | 7992826879bb |
15 | 3900531d7228 |
hex | 1c52594b50d1 |
31140011004113 has 8 divisors (see below), whose sum is σ = 34009219776960. Its totient is φ = 28277185344880.
The previous prime is 31140011004059. The next prime is 31140011004127.
31140011004113 is nontrivially palindromic in base 10.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 31140011004113 - 234 = 31122831134929 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (31140011004163) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1595768198 + ... + 1595787711.
It is an arithmetic number, because the mean of its divisors is an integer number (4251152472120).
Almost surely, 231140011004113 is an apocalyptic number.
It is an amenable number.
31140011004113 is a deficient number, since it is larger than the sum of its proper divisors (2869208772847).
31140011004113 is a wasteful number, since it uses less digits than its factorization.
31140011004113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3191556807.
The product of its (nonzero) digits is 144, while the sum is 20.
It can be divided in two parts, 3114001 and 1004113, that added together give a palindrome (4118114).
The spelling of 31140011004113 in words is "thirty-one trillion, one hundred forty billion, eleven million, four thousand, one hundred thirteen".
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