311400143011 has 4 divisors (see below), whose sum is σ = 311811504592. Its totient is φ = 310988781432.

The previous prime is 311400142987. The next prime is 311400143017. The reversal of 311400143011 is 110341004113.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 110341004113 = 1327 ⋅83150719.

It is a cyclic number.

It is not a de Polignac number, because 311400143011 - 2²³ = 311391754403 is a prime.

It is a super-2 number, since 2×311400143011² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 311400143011.

It is not an unprimeable number, because it can be changed into a prime (311400143017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 205679655 + ... + 205681168.

It is an arithmetic number, because the mean of its divisors is an integer number (77952876148).

Almost surely, 2^311400143011 is an apocalyptic number.

311400143011 is a deficient number, since it is larger than the sum of its proper divisors (411361581).

311400143011 is an equidigital number, since it uses as much as digits as its factorization.

311400143011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 411361580.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 311400143011 its reverse (110341004113), we get a palindrome (421741147124).

The spelling of 311400143011 in words is "three hundred eleven billion, four hundred million, one hundred forty-three thousand, eleven".