3114114001 has 4 divisors (see below), whose sum is σ = 3119366052. Its totient is φ = 3108861952.

The previous prime is 3114113999. The next prime is 3114114011. The reversal of 3114114001 is 1004114113.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 769230225 + 2344883776 = 27735^2 + 48424^2 .

It is a cyclic number.

It is not a de Polignac number, because 3114114001 - 2¹ = 3114113999 is a prime.

It is a super-2 number, since 2×3114114001² = 19395412022448456002, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3114114011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2625136 + ... + 2626321.

It is an arithmetic number, because the mean of its divisors is an integer number (779841513).

Almost surely, 2^3114114001 is an apocalyptic number.

It is an amenable number.

3114114001 is a deficient number, since it is larger than the sum of its proper divisors (5252051).

3114114001 is an equidigital number, since it uses as much as digits as its factorization.

3114114001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5252050.

The product of its (nonzero) digits is 48, while the sum is 16.

The square root of 3114114001 is about 55804.2471591545. The cubic root of 3114114001 is about 1460.3092484661.

Adding to 3114114001 its reverse (1004114113), we get a palindrome (4118228114).

The spelling of 3114114001 in words is "three billion, one hundred fourteen million, one hundred fourteen thousand, one".