311412212420233 has 4 divisors (see below), whose sum is σ = 311568465413908. Its totient is φ = 311255959426560.

The previous prime is 311412212420167. The next prime is 311412212420237. The reversal of 311412212420233 is 332024212214113.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 287843391538704 + 23568820881529 = 16965948^2 + 4854773^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-311412212420233 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 311412212420195 and 311412212420204.

It is not an unprimeable number, because it can be changed into a prime (311412212420237) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 78126493848 + ... + 78126497833.

It is an arithmetic number, because the mean of its divisors is an integer number (77892116353477).

Almost surely, 2^{311412212420233} is an apocalyptic number.

It is an amenable number.

311412212420233 is a deficient number, since it is larger than the sum of its proper divisors (156252993675).

311412212420233 is a wasteful number, since it uses less digits than its factorization.

311412212420233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 156252993674.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 311412212420233 its reverse (332024212214113), we get a palindrome (643436424634346).

The spelling of 311412212420233 in words is "three hundred eleven trillion, four hundred twelve billion, two hundred twelve million, four hundred twenty thousand, two hundred thirty-three".