Base | Representation |
---|---|
bin | 11101000000001110… |
… | …110101000000100011 |
3 | 2222101100220211121112 |
4 | 131000032311000203 |
5 | 1002234423300120 |
6 | 22150121413535 |
7 | 2151511014125 |
oct | 350016650043 |
9 | 88340824545 |
10 | 31142400035 |
11 | 1223108909a |
12 | 605163a2ab |
13 | 2c23c6cb56 |
14 | 1716063215 |
15 | c24087bc5 |
hex | 7403b5023 |
31142400035 has 4 divisors (see below), whose sum is σ = 37370880048. Its totient is φ = 24913920024.
The previous prime is 31142400007. The next prime is 31142400041. The reversal of 31142400035 is 53000424113.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 31142400035 - 232 = 26847432739 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3114239999 + ... + 3114240008.
It is an arithmetic number, because the mean of its divisors is an integer number (9342720012).
Almost surely, 231142400035 is an apocalyptic number.
31142400035 is a deficient number, since it is larger than the sum of its proper divisors (6228480013).
31142400035 is an equidigital number, since it uses as much as digits as its factorization.
31142400035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6228480012.
The product of its (nonzero) digits is 1440, while the sum is 23.
Adding to 31142400035 its reverse (53000424113), we get a palindrome (84142824148).
The spelling of 31142400035 in words is "thirty-one billion, one hundred forty-two million, four hundred thousand, thirty-five".
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