3114303001113 has 4 divisors (see below), whose sum is σ = 4152404001488. Its totient is φ = 2076202000740.

The previous prime is 3114303001109. The next prime is 3114303001129. The reversal of 3114303001113 is 3111003034113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 3114303001113 - 2² = 3114303001109 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 3114303001113.

It is not an unprimeable number, because it can be changed into a prime (3114304001113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 519050500183 + ... + 519050500188.

It is an arithmetic number, because the mean of its divisors is an integer number (1038101000372).

Almost surely, 2^{3114303001113} is an apocalyptic number.

It is an amenable number.

3114303001113 is a deficient number, since it is larger than the sum of its proper divisors (1038101000375).

3114303001113 is a wasteful number, since it uses less digits than its factorization.

3114303001113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1038101000374.

The product of its (nonzero) digits is 324, while the sum is 21.

Adding to 3114303001113 its reverse (3111003034113), we get a palindrome (6225306035226).

The spelling of 3114303001113 in words is "three trillion, one hundred fourteen billion, three hundred three million, one thousand, one hundred thirteen".