311431003000041 has 8 divisors (see below), whose sum is σ = 417788830201120. Its totient is φ = 206346922232832.

The previous prime is 311431003000003. The next prime is 311431003000109. The reversal of 311431003000041 is 140000300134113.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 311431003000041 - 2¹⁷ = 311431002868969 is a prime.

It is a super-2 number, since 2×311431003000041² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 311431002999981 and 311431003000017.

It is not an unprimeable number, because it can be changed into a prime (311431003000141) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 318436607896 + ... + 318436608873.

It is an arithmetic number, because the mean of its divisors is an integer number (52223603775140).

Almost surely, 2^{311431003000041} is an apocalyptic number.

It is an amenable number.

311431003000041 is a deficient number, since it is larger than the sum of its proper divisors (106357827201079).

311431003000041 is a wasteful number, since it uses less digits than its factorization.

311431003000041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 636873216935.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 311431003000041 its reverse (140000300134113), we get a palindrome (451431303134154).

The spelling of 311431003000041 in words is "three hundred eleven trillion, four hundred thirty-one billion, three million, forty-one", and thus it is an aban number.