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31143112121 = 113776518703
BaseRepresentation
bin11101000000010001…
…100010110110111001
32222101102021000102002
4131000101202312321
51002240114041441
622150144550345
72151520041152
oct350021426671
988342230362
1031143112121
11122315250a0
1260519223b5
132c2415bcc4
1417161aa929
15c24178b9b
hex740462db9

31143112121 has 8 divisors (see below), whose sum is σ = 34892529024. Its totient is φ = 27546732720.

The previous prime is 31143112057. The next prime is 31143112159. The reversal of 31143112121 is 12121134113.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 31143112121 - 26 = 31143112057 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 31143112093 and 31143112102.

It is not an unprimeable number, because it can be changed into a prime (31143112621) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 38258945 + ... + 38259758.

It is an arithmetic number, because the mean of its divisors is an integer number (4361566128).

Almost surely, 231143112121 is an apocalyptic number.

It is an amenable number.

31143112121 is a deficient number, since it is larger than the sum of its proper divisors (3749416903).

31143112121 is a wasteful number, since it uses less digits than its factorization.

31143112121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 76518751.

The product of its digits is 144, while the sum is 20.

Adding to 31143112121 its reverse (12121134113), we get a palindrome (43264246234).

The spelling of 31143112121 in words is "thirty-one billion, one hundred forty-three million, one hundred twelve thousand, one hundred twenty-one".

Divisors: 1 11 37 407 76518703 841705733 2831192011 31143112121