31143113134321 has 4 divisors (see below), whose sum is σ = 31143130316352. Its totient is φ = 31143095952292.

The previous prime is 31143113134271. The next prime is 31143113134337. The reversal of 31143113134321 is 12343131134113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 31143113134321 - 2²¹ = 31143111037169 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (31143113134621) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5501965 + ... + 9620698.

It is an arithmetic number, because the mean of its divisors is an integer number (7785782579088).

Almost surely, 2^{31143113134321} is an apocalyptic number.

It is an amenable number.

31143113134321 is a deficient number, since it is larger than the sum of its proper divisors (17182031).

31143113134321 is a wasteful number, since it uses less digits than its factorization.

31143113134321 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17182030.

The product of its digits is 7776, while the sum is 31.

Adding to 31143113134321 its reverse (12343131134113), we get a palindrome (43486244268434).

The spelling of 31143113134321 in words is "thirty-one trillion, one hundred forty-three billion, one hundred thirteen million, one hundred thirty-four thousand, three hundred twenty-one".