Base | Representation |
---|---|
bin | 100011011001111101100000… |
… | …1010101010110110010011011 |
3 | 1111211200112200022110222121111 |
4 | 1012303323001111112302123 |
5 | 311304442321442442021 |
6 | 3022205324020121151 |
7 | 122412112326316060 |
oct | 10663730125266233 |
9 | 1454615608428544 |
10 | 311431322234011 |
11 | 90260311448841 |
12 | 2ab195878361b7 |
13 | 104a0b03450485 |
14 | 56c94dc046c67 |
15 | 260109b66d8e1 |
hex | 11b3ec1556c9b |
311431322234011 has 4 divisors (see below), whose sum is σ = 355921511124592. Its totient is φ = 266941133343432.
The previous prime is 311431322233981. The next prime is 311431322234029. The reversal of 311431322234011 is 110432223134113.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 311431322234011 - 227 = 311431188016283 is a prime.
It is not an unprimeable number, because it can be changed into a prime (311431322234911) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22245094445280 + ... + 22245094445293.
It is an arithmetic number, because the mean of its divisors is an integer number (88980377781148).
Almost surely, 2311431322234011 is an apocalyptic number.
311431322234011 is a deficient number, since it is larger than the sum of its proper divisors (44490188890581).
311431322234011 is an equidigital number, since it uses as much as digits as its factorization.
311431322234011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44490188890580.
The product of its (nonzero) digits is 10368, while the sum is 31.
Adding to 311431322234011 its reverse (110432223134113), we get a palindrome (421863545368124).
The spelling of 311431322234011 in words is "three hundred eleven trillion, four hundred thirty-one billion, three hundred twenty-two million, two hundred thirty-four thousand, eleven".
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