311431401131 has 4 divisors (see below), whose sum is σ = 311438074752. Its totient is φ = 311424727512.

The previous prime is 311431401109. The next prime is 311431401137. The reversal of 311431401131 is 131104134113.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 311431401131 - 2¹⁸ = 311431138987 is a prime.

It is a super-2 number, since 2×311431401131² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 311431401097 and 311431401106.

It is not an unprimeable number, because it can be changed into a prime (311431401137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3266315 + ... + 3360308.

It is an arithmetic number, because the mean of its divisors is an integer number (77859518688).

Almost surely, 2^311431401131 is an apocalyptic number.

311431401131 is a deficient number, since it is larger than the sum of its proper divisors (6673621).

311431401131 is an equidigital number, since it uses as much as digits as its factorization.

311431401131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6673620.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 311431401131 its reverse (131104134113), we get a palindrome (442535535244).

The spelling of 311431401131 in words is "three hundred eleven billion, four hundred thirty-one million, four hundred one thousand, one hundred thirty-one".