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31143330041 = 313487204311
BaseRepresentation
bin11101000000010010…
…011000000011111001
32222101102200002100012
4131000102120003321
51002240143030131
622150153351305
72151521636405
oct350022300371
988342602305
1031143330041
111223166389a
126051a08535
132c24207255
141716226105
15c241bd52b
hex7404980f9

31143330041 has 8 divisors (see below), whose sum is σ = 31307136384. Its totient is φ = 30979933920.

The previous prime is 31143330011. The next prime is 31143330059. The reversal of 31143330041 is 14003334113.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 31143330041 - 214 = 31143313657 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 31143329989 and 31143330016.

It is not an unprimeable number, because it can be changed into a prime (31143330011) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 50276 + ... + 254586.

It is an arithmetic number, because the mean of its divisors is an integer number (3913392048).

Almost surely, 231143330041 is an apocalyptic number.

It is an amenable number.

31143330041 is a deficient number, since it is larger than the sum of its proper divisors (163806343).

31143330041 is a wasteful number, since it uses less digits than its factorization.

31143330041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 205111.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 31143330041 its reverse (14003334113), we get a palindrome (45146664154).

The spelling of 31143330041 in words is "thirty-one billion, one hundred forty-three million, three hundred thirty thousand, forty-one".

Divisors: 1 313 487 152431 204311 63949343 99499457 31143330041