Base | Representation |
---|---|
bin | 1011100110100000… |
… | …1111001111000001 |
3 | 22001001011111220011 |
4 | 2321220033033001 |
5 | 22334232124441 |
6 | 1233010544521 |
7 | 140114252254 |
oct | 27150171701 |
9 | 8031144804 |
10 | 3114333121 |
11 | 1358a61629 |
12 | 72ab98141 |
13 | 3a82a5c83 |
14 | 21788909b |
15 | 13362a581 |
hex | b9a0f3c1 |
3114333121 has 4 divisors (see below), whose sum is σ = 3114530244. Its totient is φ = 3114136000.
The previous prime is 3114333109. The next prime is 3114333133. The reversal of 3114333121 is 1213334113.
3114333121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1213334113 = 839 ⋅1446167.
It is an interprime number because it is at equal distance from previous prime (3114333109) and next prime (3114333133).
It can be written as a sum of positive squares in 2 ways, for example, as 2346433600 + 767899521 = 48440^2 + 27711^2 .
It is a cyclic number.
It is not a de Polignac number, because 3114333121 - 27 = 3114332993 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3114333092 and 3114333101.
It is not an unprimeable number, because it can be changed into a prime (3114333151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 72580 + ... + 107221.
It is an arithmetic number, because the mean of its divisors is an integer number (778632561).
Almost surely, 23114333121 is an apocalyptic number.
It is an amenable number.
3114333121 is a deficient number, since it is larger than the sum of its proper divisors (197123).
3114333121 is a wasteful number, since it uses less digits than its factorization.
3114333121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 197122.
The product of its digits is 648, while the sum is 22.
The square root of 3114333121 is about 55806.2104160460. The cubic root of 3114333121 is about 1460.3434984922.
Adding to 3114333121 its reverse (1213334113), we get a palindrome (4327667234).
The spelling of 3114333121 in words is "three billion, one hundred fourteen million, three hundred thirty-three thousand, one hundred twenty-one".
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