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31143455353051 = 74994153014449
BaseRepresentation
bin1110001010011001001101…
…00101111110100011011011
311002021021200221200012000021
413011030212211332203123
513040223244032244201
6150123034511451311
76363016566463156
oct705144645764333
9132237627605007
1031143455353051
119a17957702a68
1235ab988226b37
13144ba7a103682
147994cbcbac9d
153901a579eea1
hex1c532697e8db

31143455353051 has 4 divisors (see below), whose sum is σ = 31147608375000. Its totient is φ = 31139302331104.

The previous prime is 31143455353027. The next prime is 31143455353057. The reversal of 31143455353051 is 15035355434113.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 31143455353051 - 27 = 31143455352923 is a prime.

It is a super-2 number, since 2×311434553530512 (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 31143455352989 and 31143455353007.

It is not an unprimeable number, because it can be changed into a prime (31143455353057) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2076499726 + ... + 2076514723.

It is an arithmetic number, because the mean of its divisors is an integer number (7786902093750).

Almost surely, 231143455353051 is an apocalyptic number.

31143455353051 is a deficient number, since it is larger than the sum of its proper divisors (4153021949).

31143455353051 is an equidigital number, since it uses as much as digits as its factorization.

31143455353051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4153021948.

The product of its (nonzero) digits is 810000, while the sum is 43.

The spelling of 31143455353051 in words is "thirty-one trillion, one hundred forty-three billion, four hundred fifty-five million, three hundred fifty-three thousand, fifty-one".

Divisors: 1 7499 4153014449 31143455353051